x^2-4x+5=5x^2

Solution for x^2-4x+5=5x^2 equation:

x^2-4x+5=5x^2

We move all terms to the left:

x^2-4x+5-(5x^2)=0

determiningTheFunctionDomain
x^2-5x^2-4x+5=0

We add all the numbers together, and all the variables

-4x^2-4x+5=0

a = -4; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·(-4)·5
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{6}}{2*-4}=\frac{4-4\sqrt{6}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{6}}{2*-4}=\frac{4+4\sqrt{6}}{-8}
$